y^2+3y+14y+58=0

Solution for y^2+3y+14y+58=0 equation:

y^2+3y+14y+58=0

We add all the numbers together, and all the variables

y^2+17y+58=0

a = 1; b = 17; c = +58;
Δ = b2-4ac
Δ = 172-4·1·58
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{57}}{2*1}=\frac{-17-\sqrt{57}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{57}}{2*1}=\frac{-17+\sqrt{57}}{2}
$